Answer : Yes, the reaction occurs.
The net ionic equation will be,
[tex]2Cr^{3+}(aq)+3S^{2-}(aq)\rightarrow Cr_2S_3(s)[/tex]
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced ionic equation will be,
[tex]3Na_2S(aq)+2CrCl_3(aq)\rightarrow 6NaCl(aq)+Cr_2S_3(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]6Na^+(aq)+3S^{2-}(aq)+2Cr^{3+}(aq)+6Cl^{-}(aq)\rightarrow Cr_2S_3(s)+6Na^+(aq)+6Cl^{-}(aq)[/tex]
In this equation, [tex]Na^+\text{ and }Cl^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]2Cr^{3+}(aq)+3S^{2-}(aq)\rightarrow Cr_2S_3(s)[/tex]
