The rotors of a 15600-kg heavy-lift helicopter exert a downward force of 324000 N in order to accelerate itself and its external cargo upward at .5m/s^2. by itself, what upward force does the external cargo exert on the earth?

Respuesta :

Answer:155,391.845 N upwards to earth

Explanation:

Given

mass of rotor=15600 kg

Downward force exert by helicopter =324000 N

therefore air exerts and upward force of 324000 N

acceleration of system [tex]=0.5 m/s^2[/tex]

let m be the mass of cargo

therefore net downward force on helicopter is [tex]\left ( 15600+m\right )9.8[/tex]

Net force on helicopter

[tex]324000-\left ( 15600+m\right )9.8=\left ( 15600+m\right )\cdot 0.5[/tex]

[tex]324000=\left ( 15600+m\right )\cdot 10.3[/tex]

m=15,856.31 kg

Earth exerts a force of [tex]15,856.31\times 9.8=155,391.845 N[/tex]

Therefore cargo exerts a force of 155,391.845 N upwards to earth

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