Answer:
[tex]T_{vertical} = 50 N[/tex]
Explanation:
given,
traffic light weight = 100 N
angle at which the rope is supported = 30°
vertical component of force = ?
[tex]2 T sin \theta= W[/tex]
[tex]2 T sin 30^0= 100[/tex]
[tex]T = \dfrac{100}{2 sin 30^0}[/tex]
[tex]T = 100\ N [/tex]
[tex]T_{vertical} = T sin 30^0[/tex]
[tex]T_{vertical} = 100\times \dfrac{1}{2}[/tex]
[tex]T_{vertical} = 50 N[/tex]