Question

A particle with mass m and charge q is put into the homogenous electric field E. Assuming that at initial time the particle in rest find its velocty after the particle passes distance d.

Answer 1

Answer:

$V=\sqrt{\dfrac{2dqE}{m}}$

Explanation:

Given that

Mass = m

Electric filed = E

Initial velocity = 0 m/s

We  know that

F= q E            -----------1

F= m a          --------2

a=Acceleration

F= Force

From equation 1 and 2

q E  = m a

a= q E/m

We also know that

$V^2=V_o^2+2aS$

So

Vo = 0

V²= 0² + 2 q E/m x d

$V=\sqrt{\dfrac{2dqE}{m}}$

This is velocity of charge q after distance d .