Question

fred is playing baseball with his friends in a vacant lot. fred hits the ball at an angle of 40 degrees (at a height of 1.0m) and it crashes through the 3.4m high window of mr.jenkins house 67m away. what speed did fred give to the ball

Answer 1

Answer:

Speed, v = 26.5 m/s                    

Explanation:

It is given that,

The ball hits the ball at an angle of 40 degrees.

Initial height of the ball, h = 1 m

Vertical distance, y = 3.4 m

Horizontal distance, x = 67 m

The trajectory of the particle in projectile motion is given by :

$y=x\ tan\theta(1-\dfrac{x}{R})$

R is the range of projectile.

Putting all the values in above equation as :

$3.4=67\ tan(40)(1-\dfrac{67}{R})$      

R = 71.3 meters

Now using the formula of the range of the projectile as :

$R=\dfrac{u^2\ sin2\theta}{g}$

Substituting the values in above equation as :

$71.3=\dfrac{u^2\ sin2(40)}{9.8}$

u = 26.5 m/s

So, the speed with which Fred give to the ball is 26.5 m/s. Hence, this is the required solution.