Question

A 22.5 μF spherical capacitor is composed of two metallic spheres, one having a radius twice as large as the other. If the region between the spheres is a vacuum, determine the volume of this region. ______ m^3

Answer 1

Answer:

Volume of the sphere $=0.0347\times 10^{18}m^3$

Explanation:

We have given that capacitance of spherical capacitor $C=22.5\mu F=22.5\times 10^{-6}F$

We have to find the volume of sphere

We know that capacitance of spherical capacitance is given by $C=4\pi \epsilon _0r$

So $22.5\times 10^{-6}-4\times 3.14\times 8.85\times 10^{-12}r$

$r=0.2024\times 10^{6}m$

Now volume of sphere $V = \frac{4}{3}\pi r^3=\frac{4}{3}\times 3.14\times (0.2024\times 10^6)^3=0.0347\times 10^{18}m^3$