Question

Find the force on a 5 pС charge in a place where the electric field is 400 N/C.

Answer 1

Answer:

Electric force, $F=2\times 10^{-9}\ N$        

Explanation:

It is given that,

Charge on the particle, $q=5\ pC=5\times 10^{-12}\ C$

Electric field, $E=400\ N/C$

Let F is the electric force acting on the charged particle. The electric force per unit electric charge is called electric field. Mathematically, it is given by :

$F=qE$

$F=5\times 10^{-12}\ C\times 400\ N/C$

$F=2\times 10^{-9}\ N$

So, the force acting on the charged particle is $2\times 10^{-9}\ N$. Hence, this is the required solution.