Question

A skier speeds down a smooth ski slope which is at an angle of θ = 23° with the horizontal. The mass of the skier is 71 kg. Take the downhill direction to be positive and uphill to be negative. (a) What net force (in N) is acting on the skier? (Indicate the direction with the sign of your answer.) N (b) What is the acceleration (in m/s2) experienced by the skier? (Indicate the direction with the sign of your answer.) m/s2 (c) How does the net force experienced by the skier change if the ski slope becomes steeper? increases decreases remains the same

Answer 1

Answer:

(a) The net force is: 271.7 (i) N

(b) The acceleration is: 3.8 m/s²

(c) The net force increases

Explanation:

In order to answer the questions you have to apply Newton's Second Law:

∑F=mA

Where F is the force, m is the mass and A is the acceleration.

Applying it for the x-axis and y-axis (Where the x-axis is in the slope's direction and the y-axis is perpendicular to it)

x-axis: Wx =mA

y-axis: N-Wy=0 (because the velocity in the y-axis is constant)

Wx and Wy are the components of the weight vector.

You have to obtain the components of the weight. The slope is at an angle of 23° with the horizontal and the weight is perpendicular to the horizontal, therefore the angle formed by the weight and the slope is: 90-23=67°

Applying trigonometric identities for a right triangle to obtain the components of the weight:

Wx= mgCos(67°)=(71)(9.8)Cos(67°)=271.9 N

Wy= mgSin(67°)=(71)(9.8)Sin(67°)=640.5 N

Therefore the net force is the sum of the net force in x and the net force in y (which is zero)

F=Wx (i)

F= 271.7 N

Where i is the unit vector.

The acceleration is:

A=Wx/m=271.7/71 = 3.8 m/s²

For part (c):

If the ski slope becomes steeper it means that the angle increases. The net force is: mgCos(90-θ) which is equal to mgSin(θ). Therefore, if the angle increases then Sin(θ) increases and the force increases.

Answer 2

a) The net force acting on the skier is 271.7 (i) N

b) The acceleration experienced by the skier is 3.8 m/s²

c) if the ski slope becomes steeper, the net force increases.

What is Net force?

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

a) Apply Newton's Second Law for equilibrium of forces

∑F=ma

Where F is the force, m is the mass and a is the acceleration.

Net force in x direction:  Wx =mA

Net force in y direction: N-Wy=0

Wx and Wy are the components of the weight vector.

The slope is at an angle of 23° with the horizontal and the weight is perpendicular to the horizontal, therefore the angle formed by the weight and the slope is: 90-23=67°

The components of the weight will be:

Wx= mgCos(67°)=(71)(9.8)Cos(67°)=271.9 N

Wy= mgSin(67°)=(71)(9.8)Sin(67°)=640.5 N

Net force F=Wx (i)

F= 271.7 N

b)Acceleration a =Wx/m

a = 271.7/71

a = 3.8 m/s²

c) If the ski slope becomes steeper it means that the angle increases. The net force is: mgcos(90-θ) which is equal to mgsinθ.

Therefore, if the ski slope becomes steeper then sinθ increases and the force increases.

Learn more about net force.

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