Respuesta :
Answer:
[tex]t=0.193s[/tex]
Explanation:
What is said is that the meter fell d=18.3cm=0.183m under the action of gravity. We can use the formula for accelerated motion:
[tex]d=v_0t+\frac{at^2}{2}[/tex]
Since it departed from rest it will mean that:
[tex]d=\frac{at^2}{2}[/tex]
So our time will be:
[tex]t=\sqrt{\frac{2d}{a}}[/tex]
Which for our values is:
[tex]t=\sqrt{\frac{2(0.183m)}{(9.81m/s^2)}}=0.193s[/tex]