Answer:
Electric field, [tex]E=1.53\times 10^{10}\ N/C[/tex]
Explanation:
It is given that,
Volume of the space, [tex]V=48\ mm^3=4.8\times 10^{-8}\ m^3[/tex]
The energy stored in the electric field, U = 50 J
We know that the stored energy in the electric field per unit volume of given by :
[tex]\dfrac{U}{V}=\dfrac{1}{2}\epsilon_o E^2[/tex]
E is the electric field in this region.
[tex]E=\sqrt{\dfrac{2U}{\epsilon_o V}}[/tex]
[tex]E=\sqrt{\dfrac{2\times 50}{8.85\times 10^{-12}\times 4.8\times 10^{-8}}}[/tex]
[tex]E=1.53\times 10^{10}\ N/C[/tex]
Hence, this is the required solution.