Question

I'd appreciate it if someone could help me with this! I'm willing to give brainliest. (: Thanks!

Answer 1

Answer:

The answer to your question is: Second option   95.1g

Explanation:

Data

Mg = 24.3 g

HCl = 75 g

MgCl2 = ?

                  Mg(s)    +   2HCl(aq)   ⇒   MgCl₂(aq)    +    H₂ (g)

MW Mg = 24

MW HCl = 36.5

MW MgCl₂ = 94 g

Ratio HCl/Mg =  36.5/24 = 1.52

Theoretical ratio HCl/Mg = 75/ 24.3 = 3.08  

Then, limiting reactant = Magnesium

                24 g of Mg ------------------------94 g of MgCl₂

                24.3 g of Mg --------------------   x

                x = (24.3 x 94) / 24

                x = 95.18 g of MgCl₂

Answer 2

Answer:

95.1 g.

Explanation:

Mg + 2HCl ---> MgCl2 + H2

Using  Atomic and Molecular masses

24.3 g Mg reacts with  72.916 g of HCl to produce 95.1 g  MgCl2.

So 24.3 g of Mg  reacts with excess HCl ( 75g) to produce  95.1 g MgCl2.