Respuesta :
Answer:
Model A=30, Model B: 20, Model C: 45
Step-by-step explanation:
Let x be the amount of type A mp3 produced, and the amount of model B mp3's produced and z the amount of model C mp3 produced.
Since in total there are 303 hours for electronics work, then:
[tex]3.2x+5.4y+2.2z=303[/tex]
Since in total there are 393 hours for assembly, then:
[tex]2.8x+2.4y+5.8z=393[/tex]
Since in total there are 416 hours for quality assurance, then:
[tex]4.4x+3.4y+4.8z=416[/tex]
Then, the linear system associated to the problem is
[tex]3.2x+5.4y+2.2z=303\\2.8x+2.4y+5.8z=393\\4.4x+3.4y+4.8z=416[/tex]
with coefficient matrix [tex]A=\left[\begin{array}{ccc}3.2&5.4&2.2\\2.8&2.4&5.8\\4.4&3.4&4.8\end{array}\right][/tex] and vector of constant terms [tex]b=\left[\begin{array}{ccc}303\\393\\416\end{array}\right][/tex]
Since the determinant of A is equal to 36.704 then A is invertible.
Then for solve the system [tex]Ax=b[/tex], is enough find the inverse of A and operate
[tex]Ax=b\\A^{-1}Ax=A^{-1}b\\x=A^{-1}b[/tex]
Using Octave we obtain that
[tex]A^{-1}=\left[\begin{array}{ccc}-0.22&-0.50 &0.71\\0.33&0.15&-0.34\\-0.028& 0.35&-0.20\end{array}\right][/tex]
Then
[tex]x=A^{-1}b=\left[\begin{array}{ccc}30\\20\\45\end{array}\right][/tex]
This means that 30 mp3's of model A, 20 of model B and 45 of model C must be produced