Question

How many grams of active ingredient F should be used to prepare 135 g of a 6.7% (w/w) solution in water?

Answer 1

Answer:

We need 9.045 grams of active ingredient F to prepare a 6.7% (w/w) solution in water.

Step-by-step explanation:

6.7% (w/w) solution in water can also be expressed as: 6.7 g in 100 g of solution.

Hence:

$\frac{6.7g(F)}{100g(solution)}*135 g (solution)=9.045 g(F)$

We have to dilute 9.045 g of active ingredient F until getting 100 g of solution.