Answer:
See the procedure.
The solution is:
[tex]A=20\\B=4\\C=6[/tex]
Step-by-step explanation:
In order to solve the system using the Substitution method, you can follow these steps:
1. Substitute the second equation [tex]A=5B[/tex] and the third equation [tex]C=2B-2[/tex] into the first equation [tex]A+3B-2C=20[/tex]; and then solve for "B":
[tex](5B )+3B-2(2B-2)=20\\\\8B-4B+4=20\\\\4B=20-4\\\\B=\frac{16}{4}\\\\B=4[/tex]
2. Knowing the value of "B", substitute it into the the second equation to find "A":
[tex]A=5(4)\\\\A=20[/tex]
3. Substitute the value of "B" into the third equatio to find "C":
[tex]C=2(4)-2\\\\C=6[/tex]
