Question

An apple is dropped out of a 12 meter-high tree. How fast will the Apple be moving right before it hits the ground

Answer 1

Answer:

15.3 m/s

Explanation:

Given:

v₀ = 0 m/s

Δy = 12 m

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (12 m)

v = 15.3 m/s