Respuesta :
Answer:
13. [tex]CuCl_2 \hspace{0.1cm}+ CH_3COOAg -> AgCl \hspace{0.1cm} + (CH_3COO)_2Cu[/tex]
This is a double displacement reaction, not an acid-base reaction
14.[tex]HF\hspace{0.1cm}+Ba(OH)_2 ->\hspace{0.1cm}H_2O\hspace{0.1cm}+BaF_2[/tex]
[tex]Ba(OH)_2 -> Base[/tex]
[tex]HF -> Acid[/tex]
15. [tex]HCl\hspace{0.1cm}+Mg(OH)_2->\hspace{0.1cm}H_2O\hspace{0.1cm}+MgCl_2[/tex]
[tex]MgCl_2 -> Base[/tex]
[tex]HCl -> Acid[/tex]
16.[tex]CH_3COOH\hspace{0.1cm}+LiOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+CH_3COOLi[/tex]
[tex]LiOH -> Base[/tex]
[tex]CH_3COOH -> Acid[/tex]
17.[tex]H_2SO_4\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaHSO_4[/tex]
[tex]NaOH -> Base[/tex]
[tex]H_2SO_4-> Acid[/tex]
18. [tex]H_2SO_4\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaHSO_4[/tex]
[tex]NaOH -> Base[/tex]
[tex]H_2SO_4-> Acid[/tex]
19.[tex]H_2SO_4\hspace{0.1cm}+NaHCO3->\hspace{0.1cm}H_2O\hspace{0.1cm}+CO_2+\hspace{0.1cm}Na_2SO_4[/tex]
[tex]NaHCO_3-> Base[/tex]
[tex]H_2SO_4-> Acid[/tex]
20.[tex]H_3PO_4\hspace{0.1cm}+Zn(OH)_4->\hspace{0.1cm}H_2O\hspace{0.1cm}+Zn_3(PO_4)_4[/tex]
[tex]Zn(OH)_4> Base[/tex]
[tex]H_3PO_4-> Acid[/tex]
21. [tex]HF\hspace{0.1cm}+Na_2SO_3->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaF\hspace{0.1cm}+\hspace{0.1cm}SO_2[/tex]
[tex]NaSO_2> Base[/tex]
[tex]HF-> Acid[/tex]
22.[tex]HCl\hspace{0.1cm}+Na_2SO_3->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaCl\hspace{0.1cm}+\hspace{0.1cm}SO_2[/tex]
[tex]NaSO_2> Base[/tex]
[tex]HCl-> Acid[/tex]
23.[tex]HCl\hspace{0.1cm}+Na_2S->\hspace{0.1cm}H_2S\hspace{0.1cm}+NaCl[/tex]
[tex]Na_2S> Base[/tex]
[tex]HCl-> Acid[/tex]
24. [tex]NH_4Cl\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaCl+{0.1cm}NH_3[/tex]
[tex]NaOH> Base[/tex]
[tex]NH_4Cl-> Acid[/tex]
Explanation:
All acid-base reaction have the same products, [tex]H_2O[/tex] and a salt. Whit this in mind the acids would the compounds that produces the hydronium ion [tex](H^+)[/tex] and the bases would be the compounds that produces the hydroxide ion [tex](OH^-)[/tex]