Question

At a movie theater, admission tickets cost $10 for adults and $8 for children. On Saturday, Anne Teak collected a total of $1276 for all admissions. If she sold 52 child tickets that day, how many adult tickets did Anne sell?

a.) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold.

b.) Write an equation in two variables to model the problem that includes these 5 parts:

c.) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" in a complete sentence. Explain or show your work!

i really need help pls :(

Answer 1

Answer:

Part a) variable x (the number of adult tickets sold) and variable y (the number of child tickets sold)

Part b) $10x+8y=1,276$

Part c) The number of adult tickets sold was 86

Step-by-step explanation:

Part a) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold

Let

x -----> the number of adult tickets sold

y -----> the number of child tickets sold

Part b) Write an equation in two variables to model the problem

we know that

$10x+8y=1,276$ -----> equation A

$y=52$  -----> equation B

substitute equation B in equation A and solve for x

$10x+8(52)=1,276$

$10x+416=1,276$

Part c) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" i

we have

$10x+416=1,276$

Solve for x

Subtract 416 both sides

$10x=1,276-416$

$10x=860$

$x=86$

therefore

The number of adult tickets sold was 86