Question

During the winter months, many locations experience snow and ice storms. It is a common practice to treat roadways and sidewalks with salt, such as CaCO3 . If a 18.1 kg bag of CaCO3 is used to treat the sidewalk, how many moles of CaCO3 does this bag contain?

Answer 1

Answer:

180.845 mol

Explanation:

Molar mass of Ca: 40,078 g/mol

Molar mass of C: 12,0107 g/mol

Molar mass of O: 15,999 g/mol

Molar mass of CaCO3: (40,078+12,0107+3×15,999) 100,0857 g/mol

The number of moles= mass of bag in g ÷ molar mass of CaCO3

⇒ n= (18.1×1000)÷100,0857 = 180.845 mol