Question

How much heat is absorbed by 54g iron skillet when its temperature rises from 14°C to 28°C

Answer 1

Answer:

Approximately 340.2 joules.

Explanation:

The specific heat capacity of a substance gives the amount of heat required to raise the temperature of unit mass of that substance by unit temperature. Look up the specific heat capacity of iron in a thermodynamic data sheet.

$c(\text{Iron})\approx \rm 0.450 \; J \cdot g^{-1} \cdot {^{\circ}C}^{-1}$, where

• $\rm J$ (joule) is the unit for heat/energy,
• $\rm g$ (gram) is the unit for mass, and
• $\rm ^{\circ}C}$ degree celsius is the unit for temperature.

In other words, it takes approximately $\rm 0.450\; J$ of energy to raise the temperature of one gram of iron by one degree celsius.

In this question,

$\Delta T = 28 - 14 = \rm 14\;^{\circ}C}$.

Apply the equation:

$Q = c\cdot m \cdot \Delta T = \rm 0.450\times 14 \times 54 = 340.2\; J$.