Question

Bob sets two alarm clocks (battery-powered) to be sure he arises for his Monday 8:00 a.m. accounting exam. There is a 88 percent chance that either clock will wake Bob. (a) What is the probability that Bob will oversleep? (Round your answer to 4 decimal places.)

Answer 1

Answer:

Probability will be 0.0144

Step-by-step explanation:

We have given that the probability that there is 88 % chance that Bob wake up by either of alarm clock.

Let A Bob wake up by alarm clock 1

So P(A) = 0.88

Let B Bob wake up by alarm clock 2

So P(B) = 0.88

As we know that $P(\bar{A})=1-P(A)$

$P(\bar{A})=P(\bar{B})=1-0.88=0.12$

Here A and B are independent events and for Bob will oversleep if both clock alarm don't wake up Bob

$P(\bar{A}\cap \bar{B})=0.12\times 0.12=0.0144$