Find m∠KHG.
m∠IHG = 161°
m∠IHK = (3x + 4)°
m∠KHG = (7x + 7)°
help??
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For this case we have to, if we look at the figure, the IHG angle is given by the sum of the IHK and KHG angles.
We have to:
[tex]IHG = 161[/tex]
So, as mentioned above we have:
[tex](3x + 4) + (7x + 7) = 161\\3x + 4 + 7x + 7 = 161[/tex]
We add similar terms:
[tex]10x + 11 = 161\\10x = 161-11\\10x = 150\\x = \frac {150} {10}\\x = 15[/tex]
Thus, the KHG angle is given by:
[tex]7 (15) + 7 = 105 + 7 = 112[/tex]
Answer:
The KHG angle is 112 degrees