Answer
given,
five balls numbered 1, 2, 3, 4, and 5.
two balls are drawn randomly
number of ways of selecting two balls = ⁵C₂ = 10 ways
For sample to be of largest number there is two option 4 or 5
so for first section of ball probability will be = [tex]\dfrac{2}{5}[/tex]
now one ball is selected so for the selection of second ball the ball are 4
probability of second ball selection = [tex]\dfrac{1}{4}[/tex]
a) largest of the two sample
= [tex]\dfrac{2}{5}\times \dfrac{1}{4}[/tex]
= [tex]\dfrac{1}{10}[/tex]
=0.1
b) sum of two sample
= [tex]\dfrac{2}{5}+\dfrac{1}{4}[/tex]
= [tex]\dfrac{13}{20}[/tex]
= 0.65