Answer:
(a) [tex]a_{cA}=3.47\frac{m}{s^{2}}[/tex]
(b) [tex]F_{cA}=3507N[/tex]
(c) [tex]a_{cB}=3.47\frac{m}{s^{2}}[/tex]
(d) [tex]F_{cB}=5587N[/tex]
Explanation:
(a) Find the magnitude of the centripetal acceleration for Car A:
[tex]a_{cA}=\frac{v^{2}}{r}[/tex]
[tex]a_{cA}=\frac{(21\frac{m}{s})^{2}}{127m}[/tex]
[tex]a_{cA}=3.47\frac{m}{s^{2}}[/tex]
(b) Find the magnitude of the centripetal force for Car A:
[tex]F_{c}=m.a_{c}[/tex]
[tex]F_{cA}=m_{A}.a_{c}[/tex]
[tex]F_{cA}=1010kg*3.47\frac{m}{s^{2}}[/tex]
[tex]F=3507N[/tex]
(c) Find the magnitude of the centripetal acceleration for Car B:
As the centripetal acceleration depends of the velocity and the radius, the magnitude of the centripetal acceleration for the Car B is the same as the centripetal acceleration for the Car A.
[tex]a_{cB}=3.47\frac{m}{s^{2}}[/tex]
(d) Find the magnitude of the centripetal force for Car B:
[tex]F_{cB}=m_{B}.a_{c}[/tex]
[tex]F_{cB}=1610kg*3.47\frac{m}{s^{2}}[/tex]
[tex]F=5587N[/tex]