Question

Roberto's toy car travels at 35 centimeters per second (cm/sec) at high speed and 25 cm/sec at low speed. If the car travels for 20 seconds at high speed and then 29 seconds at low speed, what distance would the car have traveled?

Answer 1

At high speeds, the toy car would have traveled 700 centimeters (35*20=700). At low speeds, the toy car would have traveled 725 centimeters (25*29=725). In the total 49 seconds that it is traveling, it would have traveled 1,425 centimeters (700+725=1,425).

Answer 2

The total distance covered by a car is 1425 cm.

Given that, speed(S1)=35 cm/sec, speed(S2)=25 cm/sec, time(T1)=20 seconds and  time(T2)=29 seconds.

What is the formula to find the distance?

The formula to find the distance is Distance=Speed×Time.

Now, Distance(D1)=35×20=700 cm

Distance(D2)=25×29=725 cm

Thus, the total distance=700+725=1425 cm

Therefore, the total distance covered by a car is 1425 cm.

To learn more about the distance visit:

https://brainly.com/question/26711747.

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