Question

Find the slope of the line passing through the points (2, 7) and (-1, 4).

1. -1
2. 1
3. 3

Answer 1

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{7}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{2}}}\implies \cfrac{-3}{-3}\implies 1$

Answer 2

Option 2

ANSWER:  

The slope of the line passing through the points (2, 7) and (-1, 4) is 1

SOLUTION:

Given, two points are (2, 7) and (-1, 4).

We need to find the slope of a line which passes through the given two points.

Now, we know that, slope of a line which passes through the points $(x_{1} , y_{1})$ and $(x_{2} , y_{2})$ is given by

$\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { Here, in our problem, } x_{1}=-1, y_{1}=4 \text { and } x_{2}=2, y_{2}=7$

Now, substitute the above values in slope formula.

$\begin{aligned} m &=\frac{7-4}{2-(-1)} \\=& \frac{7-4}{2+1}=\frac{3}{3} \end{aligned}$

Slope “m” = 1

Hence, the slope of the required line is 1.