Answer:
H = 30.8 m
[tex] \theta =54.25^0[/tex]
Explanation:
given,
first walks straight west = 18 m
then straight in north = 25 m
the distance from the start point
H² = B² + P²
H² = 18² + 25²
[tex]H = \sqrt{18^2+25^2}[/tex]
[tex]H = \sqrt{324+625}[/tex]
H = 30.8 m
the angle between
[tex]tan \theta = \dfrac{P}{B}[/tex]
[tex]tan \theta = \dfrac{25}{18}[/tex]
[tex]\theta = tan^{-1}(\dfrac{25}{18})[/tex]
[tex] \theta =54.25^0[/tex]