Explanation:
The given data is as follows.
[tex]M_{1}[/tex] = 3 M, [tex]V_{1}[/tex] = ?
[tex]M_{2}[/tex] = 10 M, [tex]V_{2}[/tex] = 10.0 ml
Therefore, calculate the volume of given solution as follows.
[tex]M_{1} \times V_{1}[/tex] = [tex]M_{2} \times V_{2}[/tex]
Now, putting the given values into the above formula as follows.
[tex]M_{1} \times V_{1}[/tex] = [tex]M_{2} \times V_{2}[/tex]
[tex]3 M \times V_{1}[/tex] = [tex]10 M \times 10.0 ml[/tex]
[tex]V_{1}[/tex] = 33.3 ml
or, = 0.033 L (as 1 ml = 0.001 L)
Since, molarity of NaOH is given as 3 M and its volume is calculated as 33.3 ml.
Molarity = [tex]\frac{\text{mass of solute}}{\text{molar mass of solute}} \times \frac{1}{\text{volume in L}}[/tex]
3 M = [tex]\frac{mass}{40 g/mol \times 0.033 L}[/tex]
mass = 3.96 g
Therefore, we can conclude that mass of NaOH is 3.96 g.
