Answer:
C. 50%
Explanation:
Let's assume that the dominant allele "A" is responsible for the disease while the recessive allele "a" gives normal phenotype. The genotype of the affected heterozygous father would be "Aa" and the genotype of the normal mother would be "aa". A cross between Aa x aa would give progeny in the following ratio= 1/2 Aa (diseased): 1/2 aa (normal). Therefore, there are 1/2 or 50% chances for this couple to have a child affected with the autosomal dominant disease.