Determine if the following could be a probability distribution for a discrete random variable, X. If no, state why. X 20 30 40 50 P(X=x) 1.1 0.6 .2 .1 Yes, the probabilities are all positive. No, while the probabilities are all positive, the P(X=20)=1.1. Probabilities cannot exceed 1. No, the values of X are too far apart and the probabilities add up to a value greater than 1. Yes, the probabilities add to 1 and they are all positive.

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Answer:

Step-by-step explanation:

We know that the probability p of a given event is 0 ≤ p ≤1. This means that given an event, its probability should be between zero and one.

In this problem we see that P(X=20) = 1.1 which is greater than one. Therefore, this cannot be a probability distribution given that this particular case exceeds the value of 1.

For the probability distribution of a discrete random variable, X, the probability is 1.1 which is greater than 1 for X = 20.

Statement B is the correct representation of probability distribution for the discrete random variable X.

What is probability?

Probability can be defined as the possibility. It is a way to express the occurrence of a random event. The value is expressed from zero to one.

Given that probability distribution for a discrete random variable, X is,

X = 20, P(X=x) = 1.1

X = 30, P(X=x) = 0.6

X = 40, P(X=x) = 0.2

X = 50, P(X=x) = 0.1

As we know that the probability of an event occurs between 0 to 1. So, for the value of X = 20, the probability is 1.1, which cannot be a probability distribution for the given discrete random variable X.

Hence statement B is the correct representation of probability distribution for the discrete random variable X.

To know more about the probability, follow the link given below.

https://brainly.com/question/795909.

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