Respuesta :
Answer:
1) $600
2) a) 3386880 cubic yards
b) 2257920 limestone
Step-by-step explanation:
1)
Given;
Dimensions of the swimming pool = 14 feet × 30 feet
Dimensions of the pool with 3 feet wide path = ( 14 + 2 × 3 ) feet × ( 30 + 2 × 3 ) feet
= 20 feet × 36 feet
[ 2 × width of path is added because the width is to be added both the sides i.e 3 + 3 = 2 × 3 ]
Now,
The area without the path = 14 feet × 30 feet = 420 ft²
The area with the path = 20 feet × 36 feet = 720 ft²
Therefore,
the area of the path = 720 ft² - 420 ft² = 300 ft²
also,
cost to resurface = $2 per square feet
therefore,
The total cost to resurface = $2 × 300 = $600
2) Sides of the base of the pyramid = 756 feet
height of the pyramid = 480 feet
also,
1 feet = [tex]\frac{1}{3}[/tex] yards
thus,
Sides of the base of the pyramid = [tex]\frac{756}{3}[/tex] yards = 252 yards
height of the pyramid = [tex]\frac{480}{3}[/tex] yards = 160 yards
therefore,
the volume of the pyramid = [tex]\frac{\textup{1}}{\textup{3}}\times\textup{area of the base}\times\textup{height}[/tex]
= [tex]\frac{\textup{1}}{\textup{3}}\times\textup{252}^2\times\textup{160}[/tex]
= 3386880 cubic yards
b) average volume of limestone 1.5 cubic yards
Therefore,
The number of stones required = [tex]\frac{\textup{Volume of pyramid}}{\textup{volume of stone}}[/tex]
= [tex]\frac{\textup{3386880}}{\textup{1.5}}[/tex]
= 2257920 limestone