Question

An object is moving with an initial velocity of 23 m/s. It is then subject to a constant acceleration of 3.5 m/s2 for 12 s. How far will it have traveled during the time of its acceleration?

Answer 1

Answer:

528 m

Explanation:

We can solve the problem by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

In this problem,

u = 23 m/s

$a=3.5 m/s^2$

And substituting t = 12 s, we find the distance travelled:

$s=(23)(12)+\frac{1}{2}(3.5)(12)^2=528 m$