Example 9 A particle is projected from the surface of earth wl an initial speed of 4.0 km/s. Find the maximum height attained by the particle. Radius of earth 6400 km, and g 9.8m/s

Respuesta :

Answer : The maximum height attained by the particle is 935 km.

Explanation :

The formula used for the maximum height attained by the particle is,

[tex]h=\frac{v^2}{2g-\frac{v^2}{R}}[/tex]

where,

h = height of the particle = ?

v = speed of the particle = [tex]4.0km/s=4.0\times 10^3m/s[/tex]

g = acceleration due to gravity = [tex]9.8m/s^2[/tex]

R = radius of earth = [tex]6400km=64\times 10^5m[/tex]

Now put all the given values in the above formula, we get:

[tex]h=\frac{(4.0\times 10^3m/s)^2}{(2\times 9.8m/s^2)-\frac{(4.0\times 10^3m/s)^2}{64\times 10^5m}}[/tex]

[tex]h=9.35\times 10^5m=935\times 10^3m=935km[/tex]

Therefore, the maximum height attained by the particle is 935 km.

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