Respuesta :
Answer:
The profit maximizing price will be $12.
Explanation:
At the price p, the estimated quantity is,
q = 260,000 − 13,000p
The cost of each copy is $4.
Total revenue
= [tex]P\ \times\ Q[/tex]
= [tex](260,000\ -\ 13,000p)\ \times\ p[/tex]
= [tex] 260,000p\ -\ 13,000p^2 [/tex]
Total cost
= [tex]Cost\ \times\ Q[/tex]
= [tex]4\ \times\ (260,000\ \times\ 13,000p)[/tex]
= 1,040,000 - 52,000p
Marginal revenue
= [tex]\frac{d}{dp} (260,000p\ -\ 13,000p^2)[/tex]
= 260,000 - 26,000p
Marginal cost
= [tex]\frac{d}{dp}[/tex] 1,040,000 - 52,000p
= -52,000
The profit will be maximized when the marginal revenue is equal to marginal cost.
Marginal revenue = Marginal cost
260,000 - 26,000p = -52,000
26,000p = 260,000 + 52,000
26,000p = 312,000
p = 12
The price which gives the greatest profit is $12
How to find profit maximization price
- The profit maximization price is when marginal revenue is equal to marginal cost
q = 260,000 − 13,000p
C = $4
Total revenue = Price × quantity
= p × 260,000 − 13,000p
= 260,000p - 13,000p²
Marginal revenue (d/dp) = 260,000 - 26,000p
Total cost = cost × quantity
= 4 × 260,000 − 13,000p
= 1,040,000 - 52,000p
Marginal cost (d/dp) = 52,000
MR = MC
260,000 - 26,000p = 52,000
26,000p = 260,000 + 52,000
26,000p = 312,000
p = 312,000 ÷ 26,000
p = $12
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