Answer:
Three full scoring drill can be completed in [tex]\frac{5}{8}[/tex] hrs with [tex]\frac{1}{8}[/tex] hrs still remaining in end of practice session.
Solution:
Given that
Time remaining before end of soccer practice in hours = [tex]\frac{5}{8}[/tex]
Time required for 1 full scoring drill = [tex]\frac{1}{6}[/tex]
Need to identify how many drills can be complete before practice is over.
For sake of simplicity lets make denominators of both the numbers same.
[tex]\frac{5}{8}=\frac{5}{8} \times \frac{3}{3}=\frac{15}{24}[/tex]
[tex]\frac{1}{6}=\frac{1}{6} \times \frac{4}{4}=\frac{4}{24}[/tex]
[tex]\frac{4}{24}[/tex] is time for 1 drill
Lets say [tex]\frac{4}{24} = d[/tex]
Time remaining = [tex]\frac{15}{24} = \frac{4 + 4 + 4+ 3}{24} = \frac{4}{24} + \frac{4}{24} + \frac{4}{24} + \frac{3}{24} = d + d +d + \frac{3}{24}[/tex]
[tex]\frac{15}{24} = 3d + \frac{3}{24}[/tex]
3d means three drills will be completed. Fourth drill will not complete because [tex]\frac{3}{24}[/tex] is not sufficient to complete a drill.
Hence mathematical representation of given situation is
[tex]\frac{5}{8} = 3d + \frac{1}{8}[/tex]
Where d is the time required to complete one drill equal to [tex]\frac{1}{6}[/tex] of hour.
So three full scoring drill can be completed in [tex]\frac{5}{8}[/tex] hrs with [tex]\frac{1}{8}[/tex]hrs still remaining in end of practice session.