There is 5/8 of an hour before the end of soccer practice. It takes 1/6 of an hour for the team to complete 1 full scoring drill. How many drills can the team complete before practice is over? Create a model or write an equation for the situation. Find the solution. State the solution as a full sentence

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Answer:

Three full scoring drill can be completed in [tex]\frac{5}{8}[/tex] hrs with [tex]\frac{1}{8}[/tex] hrs still remaining in end of practice session.

Solution:

Given that  

Time remaining before end of soccer practice in hours = [tex]\frac{5}{8}[/tex]

Time required for 1 full scoring drill = [tex]\frac{1}{6}[/tex]

Need to identify how many drills can be complete before practice is over.

For sake of simplicity lets make denominators of both the numbers same.

[tex]\frac{5}{8}=\frac{5}{8} \times \frac{3}{3}=\frac{15}{24}[/tex]

[tex]\frac{1}{6}=\frac{1}{6} \times \frac{4}{4}=\frac{4}{24}[/tex]

[tex]\frac{4}{24}[/tex] is time for 1 drill

Lets say [tex]\frac{4}{24} = d[/tex]

Time remaining = [tex]\frac{15}{24} = \frac{4 + 4 + 4+ 3}{24} = \frac{4}{24} + \frac{4}{24} + \frac{4}{24} + \frac{3}{24} = d + d +d + \frac{3}{24}[/tex]

[tex]\frac{15}{24} = 3d + \frac{3}{24}[/tex]

3d means three drills will be completed. Fourth drill will not complete because [tex]\frac{3}{24}[/tex] is not sufficient to complete  a drill.

Hence mathematical representation of given situation is  

[tex]\frac{5}{8} = 3d + \frac{1}{8}[/tex]

Where d is the time required to complete one drill equal to [tex]\frac{1}{6}[/tex] of hour.  

So three full scoring drill can be completed in [tex]\frac{5}{8}[/tex] hrs with [tex]\frac{1}{8}[/tex]hrs still remaining in end of practice session.  

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