A bullet of mass m is traveling to the left with a speed v when it embeds itself in a block of mass M. The block sits on a frictionless surface and is connected to a spring of stiffness k. What is the compression s of the spring when the bullet and block come to rest?

Respuesta :

Answer:

given,

mass of the bullet = m

velocity of the bullet = v

mass of block = M

spring constant = k

compression of spring = ?

According to law of conservation

m v + M × 0 = ( m + M )×V

[tex]V = \dfrac{m}{m+M}v[/tex]

from law of conservation of energy

[tex]\dfrac{1}{2}(M+m)v^2 = \dfrac{1}{2}kx^2[/tex]

[tex]x = \sqrt{\dfrac{m+M}{k}}v[/tex]