Answer:
The answer to your question is:
x = 1; y = 1, z = 0
Step-by-step explanation:
-2x + 2y + 3z = 0 (I)
-2x - y + z = -3 (II)
2x + 3y + 3z = 5 (III)
I and II. Multiply II by 2
-2x + 2y + 3z = 0
(2)(-2x - y + z = -3 )
-2x + 2y + 3z = 0
-4x - 2y + 2z = -6
-6x + 5z = - 6 (IV)
II and III. Multiply II by 3
-6x - 3y + 3z = -9 (II)
2x + 3y + 3z = 5 (III)
-4x + 6z = -4 (V)
IV and V. Multiply IV by 2 and V by -3
-12x + 10z = -12
12x - 18z = 12
- 8 z = 0
z = 0
Substitute z in IV
-6x + 5(0) = -6
-6x = -6
x = 1
Substitute x and z in I
-2(1) + 2y + 3(0) = 0
-2 + 2y = 0
2y = 2
y = 1
