Answer:[tex]76.21\times 10^4 L[/tex]
Explanation:
Given
[tex]P_{initial}=752\ mm\ of\ Hg[/tex]
[tex]T_{initial}=27.8^{\circ}\approx 300.8 K[/tex]
[tex]V_{initial}=9.47\times 10^4 L[/tex]
[tex]P_{final}=73 mm\ of\ Hg[/tex]
[tex]T_{final}=235 K[/tex]
use PV=nRT
[tex]\frac{PV}{T}=constant[/tex]
[tex]\frac{P_{initial}\times V_{initial}}{T_{initial}}=\frac{P_{final}\times V_{final}}{T_{final}}[/tex]
[tex]\frac{752\times 9.47\times 10^4}{300.8}=\frac{73\times V}{235}[/tex]
[tex]V=76.21 \times 10^4 L[/tex]