Question

15. Construct the slope-intercept form equation of the line passing through (-5,23) and (10,-5).

Equation:

Answer 1

Answer:

15y = -28 x + 205.

Step-by-step explanation:

Slope intercept  form of equation is y = mx + c where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}$

Now equation of line:

y = mx + c

substituting the value of m in above expression,

$y = -\frac{28}{15} x + c$

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

$23 = -\frac{28}{15} \times (-5) + c$

$23 = \frac{28}{3} + c$

$c = 23 - \frac{28}{3} = \frac{69 - 28}{3} = \frac{41}{3}$

So equation of line in slope intercept form:

$y = -\frac{28}{15} x + \frac{41}{3}$

Further solving,

15y = -28 x + 205.