Answer:
3360 m
Explanation:
The first plane has a velocity of 660 m/h at a heading of 34.9°.
After 3 hours, the horizontal displacement is:
x₁ = (660 cos 34.9° m/h) (3 h)
x₁ = 1623.9 m
And the vertical displacement is:
y₁ = (660 sin 34.9° m/h) (3 h)
y₁ = 1132.8 m
Similarly, for the second plane:
x₂ = (560 cos 168° m/h) (3 h)
x₂ = -1643.3 m
y₂ = (560 sin 168° m/h) (3 h)
y₂ = 349.3 m
The horizontal distance between them is:
x = x₁ − x₂
x = 1623.9 m − (-1643.3 m)
x = 3267.2 m
And the vertical distance between them is:
y = y₁ − y₂
y = 1132.8 m − 349.3 m
y = 783.5 m
So the overall distance is:
d² = x² + y²
d² = (3267.2 m)² + (783.5 m)²
d = 3359.8 m
Rounding, the distance between them after 3 hours is approximately 3360 m.
