Answer:
The answer to your question is:
Empirical formula: C₁ H₁.₃O₁
Molecular formula: C₆H₈O₆
Explanation:
Ascorbic acid (C, H, and O)
5.24 g of ascorbic acid
7.86 g of CO2
2.14 g of H2O
Empirical formula = ?
Molecular formula = ?
Molecular mass = 176 g/mol
MW CO2 = 44 g
MW H2O = 18 g
44 g of CO2 ------------------ 12 g of C
7.86 g of CO2 --------------- x
x = (7.86 x 12) / 44
x = 2.14 g of Carbon
18 g of water ----------------- 2 g of H
2.14 g of water -------------- x
x = (2.14 x 2) / 18
x = 0.24 g of H
Mass of Oxygen = 5.24 - 2.14 - 0.24
Mass of Oxygen = 2.86 g of Oxygen
Moles
12 g of C -------------1 mol
2.14 g -------------- x
x = 2.14 / 12
x = 0.18 moles of Carbon
1 g of H --------------- 1 mol
0.24 g ----------------- x
x = 0.24 / 1
x = 0.24 moles of H
16 g of O ------------- 1 mol
2.86 g ------------- x
x = 2.86/ 16
x = 0.18 moles of oxygen
Divide by the lowest number of moles
Carbon = 0.18/ 0.18 = 1
Hydrogen = 0.24/0.18 = 1.3
Oxygen = 0.18/0.18 = 1
Oxygen = 0.18 / 0.18
C₁ H₁.₃O₁
Molecular formula
C = 12; H = 1.3 ; O = 16 MW = 29.6
Molar mass/ MW 176/ 29.6 = 6
C₆H₈O₆
