A cruise ship is currently 20 kilometers away from its port and is traveling away from the port at 5 kilometers per hour . The function is y=5x +20 relates the number of kilometers y the ship will be from its port x hours from now. How far will the cruise ship be from its port 3.5 hours from now

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Answer:

The ship will be [tex]37.5\ km[/tex] far from its port 3.5 hours from now

Step-by-step explanation:

Hi

The function is [tex]y=5x +20[/tex] relates the number of kilometers y the ship will be from its port x hours from now, it has a form [tex]y=vt+y_{0} \ where \ y\ is\ final\ distance\\v\ is\ velocity\ in\ km/h,\ t\ is\ time\\and\ y_{0}\ is\ initial\ distance[/tex].

As the function is clearly defined, we only have to evaluate it for [tex]x=3.5[/tex], so [tex]y(3.5)=5(3.5)+20=17.5+20=37.5 \ km[/tex] is the distance between the cruise ship and its port after 3.5 hours.