Answer:
The answer to your question is: yield = 81 %
Explanation:
Data
Calcium oxide mass = 2 g
Calcium hydroxide mass = 2.14 g
yield = ?
Process
Reaction
CaO + H₂O ⇒ Ca(OH)₂
MW CaO = 40 + 16 = 56 g
MW Ca(OH)₂ = 40 + 32 + 2 = 74 g
56 g of CaO ----------------- 74 g of Ca(OH)₂
2 g ---------------- x
x = (2 x 74)/ 56
x = 2.64 g of Ca(OH)₂
yield = experimental / theoretical x 100
yield = 2.14 / 2.64 x 100
yield = 81 %