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Answer:

  • The general molecular formula for cycloalkanes with two rings is:

         [tex]C_nH_{2n-2}[/tex]

Explanation:

As stated in the question statement, the general formula for an alkane is:

        [tex]C_nH_{2n+2}[/tex]

That is because each of the two carbons of the ends are bonded to three hydrogen atoms and the other carbons are bonded to two atoms:

This example shows you how that works.

Assume a four carbon linear chain, i.e. n = 4:

  • Two carbons of the ends ↔ six hydrogens
  • Two internal carbons ↔ four hydrogens
  • 2 + 2 = 4 carbons ↔ 6 + 4 = 10 hydrogens
  • 4 ↔ 2×4 + 2

For an alkane of one ring or with one ring, the general formula is:

        [tex]C_nH_{2n}[/tex]

That is because there not ending carbons: every carbon atom is attached to other carbon atom and two hydrogen atoms.

If you add a second ring, the molecule will have two less hydrogen atoms relative to the alkance with one ring, because you are adding one extra carbon - carbon bond, reducing the number of hydrogen atoms attached in two.

Thus, the general formula for cycloalkanes with two rings is:

        [tex]C_nH_{2n-2}[/tex]

Answer:

[tex]\huge \boxed{{C_nH_{2n-2}}}[/tex]

Explanation:

The formula for one ring cycloalkanes is:

[tex]C_nH_{2n}[/tex]

Cycloalkanes with two rings have two less hydrogen atoms.

[tex]C_nH_{2n-2}[/tex]

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