Question

Calculate the net force of the following situation. ←10 Newtons + →30 Newtons
Question 1 options:

←40 Newtons


←20 Newtons


→40 Newtons


→20 Newtons

Answer 1

Answer:

The net force will be 20 N.

Explanation:

Given data:

F  = 30 N

F = 10 N

ΣF = ?

Solution:

Formula:

ΣF = + F  - F

ΣF = 30 N - 10 N

ΣF = 20 N

The net force will be 20 N.

Answer 2

Answer:

→20 Newtons

Explanation:

These are two vectors are in opposite directions. Let's say;

 $V_{1}$ = 10 N

 $V_{2}$ = 30N

But $V_{2}$ moves in the positive direction (given in the question) as against tht of $V_{1}$, so:

   $V_{1}$ = - 10 N

   $V_{2}$ = + 30N

The net force =  $V_{1}$ + $V_{2}$

                       = -10 + 30

                       = + 20N

This shows that the net force is in the direction of force $V_{2}$ .

Thus, net force is →20 Newtons