Answers:
a) [tex]4.132 m/s[/tex]
b) [tex]0.377 m/s^{2} [/tex]
Explanation:
a) Average velocity [tex]V[/tex] is expressed by the following equation:
[tex]V=\frac{d}{t}[/tex]
Where:
[tex]d=29752 m[/tex] is Maurizio's displacement
[tex]t=2h \frac{3600 s}{1 h}=7200 s[/tex] is the time
[tex]V=\frac{29752 m}{7200 s}[/tex]
Hence:
[tex]4.132 m/s[/tex]
b) Average acceleration [tex]a_{ave}[/tex] is the variation of velocity [tex]\Delta V[/tex] over a specified period of time [tex]\Delta t[/tex]:
[tex]a_{ave}=\frac{\Delta V}{\Delta t}}[/tex]
Where:
[tex]\Delta V=V-V_{o}[/tex] being [tex]V_{o}=3 m/s[/tex] the initial velocity and [tex]V=4.132 m/s[/tex] the final velocity
[tex]\Delta t=3 s[/tex]
Then:
[tex]a_{ave}=\frac{4.132 m/s - 3 m/s}{3 s}[/tex]
[tex]a_{ave}=0.377 m/s^{2} [/tex]