Respuesta :

Answer:

Top left

Step-by-step explanation:

We can plug in the y intercept to find which graph has the correct one.

x = 0 is y intercept

Thus

[tex]f(0) = -3^0-2 \\f(0) = -1-2\\f(0)=-3[/tex]

At this point we known the y intercept is -3 so both graph in the left is considerable.

Notice that the base is the negative, thus the graph would goes down. Therefore the top left would be correct.

When a vertical line is moved across the network only and touches its graph at one point at any given time, the graph is a function. If the dotted axis intersects the network at more than one place, then the graph is not a function.

  • You may use the y-intercept to verify which graph does have the proper one.
  • x = 0 is the y-intercept. thus,

           [tex]\to f(0)=-3^{0}-2= -1-2= -3\\\\[/tex]

  • so, the points are (0,-3).
  • At this point, we know the y-intercept is -3, so both graphs on the left are significant.

Therefore, the answer is "first graph"

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