Answer:
a) 0.2713
b)Zombie Infection and Ragnarok, Ragnarok and UFO invasion.
Step-by-step explanation:
We are given the following information in the question:
There is a 10% chance of a zombie infection. There is a 12% chance of Ragnarok . There is an 8% chance of a UFO invasion.
Thus, we can write:
P(A) = P(Zombie Infection) = 10% = 0.10
P(B) = P(Ragnarok) = 12% = 0.12
P(C) = P(UFO Invasion) = 8% = 0.08
It is given that all three events are independent.
a) P(an apocalypse of one sort or another)
[tex]P(A \cup B \cup C) = P(A) + P(B) + P(C) + -P(A \cup B) - P{A \cup C) - P(B \cup C)[/tex]
Since the events are independent
[tex]P(A \cup B \cup C) \\\\=P(A) + P(B) + P(C) - (P(A)\times P(B) + P(A)\times P(C) + P(B)\times P(C))\\\\=0.10 + 0.12 + 0.08 - (0.10\times 0.12) - (0.10\times 0.08) - (0.08\times 0.12)\\\\= 0.2713[/tex]
b)
[tex]P(A \cap B) = P(A)\times P(B) = 0.10\times 0.12 = 0.012\\P(A \cap C) = P(A)\times P(C) = 0.10\times 0.08 = 0.008\\P(B \cap C) =P(B)\times P(C) = 0.12\times 0.08 = 0.0096[/tex]
Now, want a combination of apocalypse such that probability is greater than or equal to 0.009.
P( Combination ) > 0.009
Thus, the possible combination of apocalypse are:
Zombie Infection and Ragnarok
Ragnarok and UFO invasion.