Answer:
The probability that the sum of the numbers is either 7 or 11 is 0.22.
Step-by-step explanation:
To have this kind of event you can have the following events, where (d1,d2) d1 is the number that appears uppermost on die 1 and d2 is the number that appears uppermost on dice 2: (1,6); (6,1); (2,5); (5,2); (3,4); (4,3); (5,6); (6,5), the total number of events is 36 since every dice have 6 numbers.
The probability is:
P(Event)=P(sum is 7 or 11)/Total number of events
P=8/36=0.22
