Respuesta :
Answer:
sol. with highest pH is sol.of 100 mL of water with 20 mL of 0.1 M NaOH
Explanation:
A solution of 100 ml of water with 20 ml of 0.1 M NaOH
we know that[tex]M_1 V_1 = M_2 V_2[/tex]
0.1(20) = M_2(120)
[tex]M_2 = 0.017 M[/tex]
[tex][OH^-] = 0.017 M[/tex]
pOH = 1.77
pH = 14 - 1.77 = 12.23
A buffer solution of [/tex]0.1 M HClO, 0.1 M ClO^{-}[/tex]
[tex]pH = pK_a + log\frac{[salt]}{[acid]}[/tex]
[tex] = -log\3.8\times 10^{-8} + log\frac{0.1}{0.1}[/tex]
pH = 7.42
Additio of strong base will increase the pH of buffer sol. But increase in pH is veery small
Additio of strong base will increase the pH of buffer sol. But increase in pH is small
Additio of strong acid will lower the pH of buffer sol. But increase in pH is veery small
Therefore sol. with highest pH is sol.of 100 mL of water with 20 mL of 0.1 M NaOH
The highest pH contributes to the addition of base, while acid decreases the pH. The highest pH is contributed to 0.1 M NaOH.
What is a pH?
The pH has been the concentration of the hydrogen ion in the solution. It can be given as the negative logarithmic concentration of hydrogen ion.
The pH of solution can be calculated as:
[tex]\rm M_1V_1=M_2V_2\\0.1\;\times\;20=M_2\;\times\;120\\M_2=0.017\;M[/tex]
The molarity of hydroxide ion in NaOH has been equal to 0.017 M.
The pH can be given as:
[tex]\rm pH=14-pOH\\pH-14-0.017\\pH=12.23[/tex]
The pH of NaOH solution is 12.23.
The pH of HClO solution with the ClO ion has been:
[tex]\rm pH=pKa+log\dfrac{acid}{salt}\\ pH=-log\;3.8\;\times\;10^-^8\;log\dfrac{0.1}{0.1}\\ pH=7.42[/tex]
The pH of HClO solution has been 7.42.
The pH of buffer can be given as, addition of strong acid and base alters the pH to the very low degree. Thus, the pH had been found maximum for the NaOH solution.
Thus, option A is correct.
Learn more about, pH here:
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