Question

Find the solution of the square root of the quantity of x plus 3 plus 6 equals 9 and determine if it is an extraneous solution. ( A. x=0 extraneous; B. x=0 non-extraneous; C. x=6 extraneous; D. x=6 non-extraneous)

Answer 1

√(x+3)+6=9
minus 6 both sides
√(x+3)=3
squar both sides
x+3=+/-9
minus 3 both sides
x=6 or -12

sub to see
√(6+3)+6=9
√(9)+6=9
3+6=9
9=9
true

other one
√(-12+9)+6=9
√(-9)+6=9
false (means this is an extranious answer)


x=6 and it is not extranious
D


72 is anres

Answer 2

Answer:

X=6 not extraneous